Metamath Proof Explorer
Theorem nfi
Description: Deduce that x is not free in ph from the definition.
(Contributed by Wolf Lammen, 15-Sep-2021)
|
|
Ref |
Expression |
|
Hypothesis |
nfi.1 |
⊢ ( ∃ 𝑥 𝜑 → ∀ 𝑥 𝜑 ) |
|
Assertion |
nfi |
⊢ Ⅎ 𝑥 𝜑 |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
nfi.1 |
⊢ ( ∃ 𝑥 𝜑 → ∀ 𝑥 𝜑 ) |
2 |
|
df-nf |
⊢ ( Ⅎ 𝑥 𝜑 ↔ ( ∃ 𝑥 𝜑 → ∀ 𝑥 𝜑 ) ) |
3 |
1 2
|
mpbir |
⊢ Ⅎ 𝑥 𝜑 |