Metamath Proof Explorer


Theorem nfntht

Description: Closed form of nfnth . (Contributed by BJ, 16-Sep-2021) (Proof shortened by Wolf Lammen, 4-Sep-2022)

Ref Expression
Assertion nfntht ( ¬ ∃ 𝑥 𝜑 → Ⅎ 𝑥 𝜑 )

Proof

Step Hyp Ref Expression
1 pm2.21 ( ¬ ∃ 𝑥 𝜑 → ( ∃ 𝑥 𝜑 → ∀ 𝑥 𝜑 ) )
2 1 nfd ( ¬ ∃ 𝑥 𝜑 → Ⅎ 𝑥 𝜑 )