Metamath Proof Explorer
Description: Closed form of nfnth . (Contributed by BJ, 16-Sep-2021) (Proof
shortened by Wolf Lammen, 4-Sep-2022)
|
|
Ref |
Expression |
|
Assertion |
nfntht |
⊢ ( ¬ ∃ 𝑥 𝜑 → Ⅎ 𝑥 𝜑 ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
pm2.21 |
⊢ ( ¬ ∃ 𝑥 𝜑 → ( ∃ 𝑥 𝜑 → ∀ 𝑥 𝜑 ) ) |
| 2 |
1
|
nfd |
⊢ ( ¬ ∃ 𝑥 𝜑 → Ⅎ 𝑥 𝜑 ) |