Metamath Proof Explorer


Theorem nnm0

Description: Multiplication with zero. Theorem 4J(A1) of Enderton p. 80. (Contributed by NM, 20-Sep-1995)

Ref Expression
Assertion nnm0 ( 𝐴 ∈ ω → ( 𝐴 ·o ∅ ) = ∅ )

Proof

Step Hyp Ref Expression
1 nnon ( 𝐴 ∈ ω → 𝐴 ∈ On )
2 om0 ( 𝐴 ∈ On → ( 𝐴 ·o ∅ ) = ∅ )
3 1 2 syl ( 𝐴 ∈ ω → ( 𝐴 ·o ∅ ) = ∅ )