Step |
Hyp |
Ref |
Expression |
1 |
|
nnmwordi |
⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ∧ 𝐶 ∈ ω ) → ( 𝐴 ⊆ 𝐵 → ( 𝐶 ·o 𝐴 ) ⊆ ( 𝐶 ·o 𝐵 ) ) ) |
2 |
|
nnmcom |
⊢ ( ( 𝐴 ∈ ω ∧ 𝐶 ∈ ω ) → ( 𝐴 ·o 𝐶 ) = ( 𝐶 ·o 𝐴 ) ) |
3 |
2
|
3adant2 |
⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ∧ 𝐶 ∈ ω ) → ( 𝐴 ·o 𝐶 ) = ( 𝐶 ·o 𝐴 ) ) |
4 |
|
nnmcom |
⊢ ( ( 𝐵 ∈ ω ∧ 𝐶 ∈ ω ) → ( 𝐵 ·o 𝐶 ) = ( 𝐶 ·o 𝐵 ) ) |
5 |
4
|
3adant1 |
⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ∧ 𝐶 ∈ ω ) → ( 𝐵 ·o 𝐶 ) = ( 𝐶 ·o 𝐵 ) ) |
6 |
3 5
|
sseq12d |
⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ∧ 𝐶 ∈ ω ) → ( ( 𝐴 ·o 𝐶 ) ⊆ ( 𝐵 ·o 𝐶 ) ↔ ( 𝐶 ·o 𝐴 ) ⊆ ( 𝐶 ·o 𝐵 ) ) ) |
7 |
1 6
|
sylibrd |
⊢ ( ( 𝐴 ∈ ω ∧ 𝐵 ∈ ω ∧ 𝐶 ∈ ω ) → ( 𝐴 ⊆ 𝐵 → ( 𝐴 ·o 𝐶 ) ⊆ ( 𝐵 ·o 𝐶 ) ) ) |