Metamath Proof Explorer


Theorem notbii

Description: Negate both sides of a logical equivalence. (Contributed by NM, 3-Jan-1993) (Proof shortened by Wolf Lammen, 19-May-2013)

Ref Expression
Hypothesis notbii.1 ( 𝜑𝜓 )
Assertion notbii ( ¬ 𝜑 ↔ ¬ 𝜓 )

Proof

Step Hyp Ref Expression
1 notbii.1 ( 𝜑𝜓 )
2 notbi ( ( 𝜑𝜓 ) ↔ ( ¬ 𝜑 ↔ ¬ 𝜓 ) )
3 1 2 mpbi ( ¬ 𝜑 ↔ ¬ 𝜓 )