Metamath Proof Explorer


Theorem npcan1

Description: Cancellation law for subtraction and addition with 1. (Contributed by Alexander van der Vekens, 5-Oct-2018)

Ref Expression
Assertion npcan1 ( 𝐴 ∈ ℂ → ( ( 𝐴 − 1 ) + 1 ) = 𝐴 )

Proof

Step Hyp Ref Expression
1 id ( 𝐴 ∈ ℂ → 𝐴 ∈ ℂ )
2 1cnd ( 𝐴 ∈ ℂ → 1 ∈ ℂ )
3 1 2 npcand ( 𝐴 ∈ ℂ → ( ( 𝐴 − 1 ) + 1 ) = 𝐴 )