Metamath Proof Explorer


Theorem nppcan3d

Description: Cancellation law for subtraction. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses negidd.1 ( 𝜑𝐴 ∈ ℂ )
pncand.2 ( 𝜑𝐵 ∈ ℂ )
subaddd.3 ( 𝜑𝐶 ∈ ℂ )
Assertion nppcan3d ( 𝜑 → ( ( 𝐴𝐵 ) + ( 𝐶 + 𝐵 ) ) = ( 𝐴 + 𝐶 ) )

Proof

Step Hyp Ref Expression
1 negidd.1 ( 𝜑𝐴 ∈ ℂ )
2 pncand.2 ( 𝜑𝐵 ∈ ℂ )
3 subaddd.3 ( 𝜑𝐶 ∈ ℂ )
4 nppcan3 ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ ) → ( ( 𝐴𝐵 ) + ( 𝐶 + 𝐵 ) ) = ( 𝐴 + 𝐶 ) )
5 1 2 3 4 syl3anc ( 𝜑 → ( ( 𝐴𝐵 ) + ( 𝐶 + 𝐵 ) ) = ( 𝐴 + 𝐶 ) )