Metamath Proof Explorer
		
		
		Theorem nvm
		Description:  Vector subtraction in terms of group division operation.  (Contributed by NM, 15-Feb-2008)  (New usage is discouraged.)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | nvm.1 | ⊢ 𝑋  =  ( BaseSet ‘ 𝑈 ) | 
					
						|  |  | nvm.2 | ⊢ 𝐺  =  (  +𝑣  ‘ 𝑈 ) | 
					
						|  |  | nvm.3 | ⊢ 𝑀  =  (  −𝑣  ‘ 𝑈 ) | 
					
						|  |  | nvm.6 | ⊢ 𝑁  =  (  /𝑔  ‘ 𝐺 ) | 
				
					|  | Assertion | nvm | ⊢  ( ( 𝑈  ∈  NrmCVec  ∧  𝐴  ∈  𝑋  ∧  𝐵  ∈  𝑋 )  →  ( 𝐴 𝑀 𝐵 )  =  ( 𝐴 𝑁 𝐵 ) ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | nvm.1 | ⊢ 𝑋  =  ( BaseSet ‘ 𝑈 ) | 
						
							| 2 |  | nvm.2 | ⊢ 𝐺  =  (  +𝑣  ‘ 𝑈 ) | 
						
							| 3 |  | nvm.3 | ⊢ 𝑀  =  (  −𝑣  ‘ 𝑈 ) | 
						
							| 4 |  | nvm.6 | ⊢ 𝑁  =  (  /𝑔  ‘ 𝐺 ) | 
						
							| 5 | 2 3 | vsfval | ⊢ 𝑀  =  (  /𝑔  ‘ 𝐺 ) | 
						
							| 6 | 5 4 | eqtr4i | ⊢ 𝑀  =  𝑁 | 
						
							| 7 | 6 | oveqi | ⊢ ( 𝐴 𝑀 𝐵 )  =  ( 𝐴 𝑁 𝐵 ) | 
						
							| 8 | 7 | a1i | ⊢ ( ( 𝑈  ∈  NrmCVec  ∧  𝐴  ∈  𝑋  ∧  𝐵  ∈  𝑋 )  →  ( 𝐴 𝑀 𝐵 )  =  ( 𝐴 𝑁 𝐵 ) ) |