Metamath Proof Explorer


Theorem off2

Description: The function operation produces a function - alternative form with all antecedents as deduction. (Contributed by Thierry Arnoux, 17-Feb-2017)

Ref Expression
Hypotheses off2.1 ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑆 ∧ 𝑦 ∈ 𝑇 ) ) → ( 𝑥 𝑅 𝑦 ) ∈ 𝑈 )
off2.2 ⊢ ( 𝜑 → 𝐹 : 𝐴 ⟶ 𝑆 )
off2.3 ⊢ ( 𝜑 → 𝐺 : 𝐵 ⟶ 𝑇 )
off2.4 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
off2.5 ⊢ ( 𝜑 → 𝐵 ∈ 𝑊 )
off2.6 ⊢ ( 𝜑 → ( 𝐴 ∩ 𝐵 ) = 𝐶 )
Assertion off2 ( 𝜑 → ( 𝐹 ∘f 𝑅 𝐺 ) : 𝐶 ⟶ 𝑈 )

Proof

Step Hyp Ref Expression
1 off2.1 ⊢ ( ( 𝜑 ∧ ( 𝑥 ∈ 𝑆 ∧ 𝑦 ∈ 𝑇 ) ) → ( 𝑥 𝑅 𝑦 ) ∈ 𝑈 )
2 off2.2 ⊢ ( 𝜑 → 𝐹 : 𝐴 ⟶ 𝑆 )
3 off2.3 ⊢ ( 𝜑 → 𝐺 : 𝐵 ⟶ 𝑇 )
4 off2.4 ⊢ ( 𝜑 → 𝐴 ∈ 𝑉 )
5 off2.5 ⊢ ( 𝜑 → 𝐵 ∈ 𝑊 )
6 off2.6 ⊢ ( 𝜑 → ( 𝐴 ∩ 𝐵 ) = 𝐶 )
7 2 ffnd ⊢ ( 𝜑 → 𝐹 Fn 𝐴 )
8 3 ffnd ⊢ ( 𝜑 → 𝐺 Fn 𝐵 )
9 eqid ⊢ ( 𝐴 ∩ 𝐵 ) = ( 𝐴 ∩ 𝐵 )
10 eqidd ⊢ ( ( 𝜑 ∧ 𝑧 ∈ 𝐴 ) → ( 𝐹 ‘ 𝑧 ) = ( 𝐹 ‘ 𝑧 ) )
11 eqidd ⊢ ( ( 𝜑 ∧ 𝑧 ∈ 𝐵 ) → ( 𝐺 ‘ 𝑧 ) = ( 𝐺 ‘ 𝑧 ) )
12 7 8 4 5 9 10 11 offval ⊢ ( 𝜑 → ( 𝐹 ∘f 𝑅 𝐺 ) = ( 𝑧 ∈ ( 𝐴 ∩ 𝐵 ) ↦ ( ( 𝐹 ‘ 𝑧 ) 𝑅 ( 𝐺 ‘ 𝑧 ) ) ) )
13 6 mpteq1d ⊢ ( 𝜑 → ( 𝑧 ∈ ( 𝐴 ∩ 𝐵 ) ↦ ( ( 𝐹 ‘ 𝑧 ) 𝑅 ( 𝐺 ‘ 𝑧 ) ) ) = ( 𝑧 ∈ 𝐶 ↦ ( ( 𝐹 ‘ 𝑧 ) 𝑅 ( 𝐺 ‘ 𝑧 ) ) ) )
14 12 13 eqtrd ⊢ ( 𝜑 → ( 𝐹 ∘f 𝑅 𝐺 ) = ( 𝑧 ∈ 𝐶 ↦ ( ( 𝐹 ‘ 𝑧 ) 𝑅 ( 𝐺 ‘ 𝑧 ) ) ) )
15 2 adantr ⊢ ( ( 𝜑 ∧ 𝑧 ∈ 𝐶 ) → 𝐹 : 𝐴 ⟶ 𝑆 )
16 inss1 ⊢ ( 𝐴 ∩ 𝐵 ) ⊆ 𝐴
17 6 16 eqsstrrdi ⊢ ( 𝜑 → 𝐶 ⊆ 𝐴 )
18 17 sselda ⊢ ( ( 𝜑 ∧ 𝑧 ∈ 𝐶 ) → 𝑧 ∈ 𝐴 )
19 15 18 ffvelcdmd ⊢ ( ( 𝜑 ∧ 𝑧 ∈ 𝐶 ) → ( 𝐹 ‘ 𝑧 ) ∈ 𝑆 )
20 3 adantr ⊢ ( ( 𝜑 ∧ 𝑧 ∈ 𝐶 ) → 𝐺 : 𝐵 ⟶ 𝑇 )
21 inss2 ⊢ ( 𝐴 ∩ 𝐵 ) ⊆ 𝐵
22 6 21 eqsstrrdi ⊢ ( 𝜑 → 𝐶 ⊆ 𝐵 )
23 22 sselda ⊢ ( ( 𝜑 ∧ 𝑧 ∈ 𝐶 ) → 𝑧 ∈ 𝐵 )
24 20 23 ffvelcdmd ⊢ ( ( 𝜑 ∧ 𝑧 ∈ 𝐶 ) → ( 𝐺 ‘ 𝑧 ) ∈ 𝑇 )
25 1 ralrimivva ⊢ ( 𝜑 → ∀ 𝑥 ∈ 𝑆 ∀ 𝑦 ∈ 𝑇 ( 𝑥 𝑅 𝑦 ) ∈ 𝑈 )
26 25 adantr ⊢ ( ( 𝜑 ∧ 𝑧 ∈ 𝐶 ) → ∀ 𝑥 ∈ 𝑆 ∀ 𝑦 ∈ 𝑇 ( 𝑥 𝑅 𝑦 ) ∈ 𝑈 )
27 ovrspc2v ⊢ ( ( ( ( 𝐹 ‘ 𝑧 ) ∈ 𝑆 ∧ ( 𝐺 ‘ 𝑧 ) ∈ 𝑇 ) ∧ ∀ 𝑥 ∈ 𝑆 ∀ 𝑦 ∈ 𝑇 ( 𝑥 𝑅 𝑦 ) ∈ 𝑈 ) → ( ( 𝐹 ‘ 𝑧 ) 𝑅 ( 𝐺 ‘ 𝑧 ) ) ∈ 𝑈 )
28 19 24 26 27 syl21anc ⊢ ( ( 𝜑 ∧ 𝑧 ∈ 𝐶 ) → ( ( 𝐹 ‘ 𝑧 ) 𝑅 ( 𝐺 ‘ 𝑧 ) ) ∈ 𝑈 )
29 14 28 fmpt3d ⊢ ( 𝜑 → ( 𝐹 ∘f 𝑅 𝐺 ) : 𝐶 ⟶ 𝑈 )