Metamath Proof Explorer


Theorem omlsilem

Description: Lemma for orthomodular law in the Hilbert lattice. (Contributed by NM, 14-Oct-1999) (New usage is discouraged.)

Ref Expression
Hypotheses omlsilem.1 ⊢ 𝐺 ∈ Sℋ
omlsilem.2 ⊢ 𝐻 ∈ Sℋ
omlsilem.3 ⊢ 𝐺 ⊆ 𝐻
omlsilem.4 ⊢ ( 𝐻 ∩ ( ⊥ ‘ 𝐺 ) ) = 0ℋ
omlsilem.5 ⊢ 𝐴 ∈ 𝐻
omlsilem.6 ⊢ 𝐵 ∈ 𝐺
omlsilem.7 ⊢ 𝐶 ∈ ( ⊥ ‘ 𝐺 )
Assertion omlsilem ( 𝐴 = ( 𝐵 +ℎ 𝐶 ) → 𝐴 ∈ 𝐺 )

Proof

Step Hyp Ref Expression
1 omlsilem.1 ⊢ 𝐺 ∈ Sℋ
2 omlsilem.2 ⊢ 𝐻 ∈ Sℋ
3 omlsilem.3 ⊢ 𝐺 ⊆ 𝐻
4 omlsilem.4 ⊢ ( 𝐻 ∩ ( ⊥ ‘ 𝐺 ) ) = 0ℋ
5 omlsilem.5 ⊢ 𝐴 ∈ 𝐻
6 omlsilem.6 ⊢ 𝐵 ∈ 𝐺
7 omlsilem.7 ⊢ 𝐶 ∈ ( ⊥ ‘ 𝐺 )
8 2 5 shelii ⊢ 𝐴 ∈ ℋ
9 1 6 shelii ⊢ 𝐵 ∈ ℋ
10 shocss ⊢ ( 𝐺 ∈ Sℋ → ( ⊥ ‘ 𝐺 ) ⊆ ℋ )
11 1 10 ax-mp ⊢ ( ⊥ ‘ 𝐺 ) ⊆ ℋ
12 11 7 sselii ⊢ 𝐶 ∈ ℋ
13 8 9 12 hvsubaddi ⊢ ( ( 𝐴 −ℎ 𝐵 ) = 𝐶 ↔ ( 𝐵 +ℎ 𝐶 ) = 𝐴 )
14 eqcom ⊢ ( ( 𝐵 +ℎ 𝐶 ) = 𝐴 ↔ 𝐴 = ( 𝐵 +ℎ 𝐶 ) )
15 13 14 bitri ⊢ ( ( 𝐴 −ℎ 𝐵 ) = 𝐶 ↔ 𝐴 = ( 𝐵 +ℎ 𝐶 ) )
16 3 6 sselii ⊢ 𝐵 ∈ 𝐻
17 shsubcl ⊢ ( ( 𝐻 ∈ Sℋ ∧ 𝐴 ∈ 𝐻 ∧ 𝐵 ∈ 𝐻 ) → ( 𝐴 −ℎ 𝐵 ) ∈ 𝐻 )
18 2 5 16 17 mp3an ⊢ ( 𝐴 −ℎ 𝐵 ) ∈ 𝐻
19 eleq1 ⊢ ( ( 𝐴 −ℎ 𝐵 ) = 𝐶 → ( ( 𝐴 −ℎ 𝐵 ) ∈ 𝐻 ↔ 𝐶 ∈ 𝐻 ) )
20 18 19 mpbii ⊢ ( ( 𝐴 −ℎ 𝐵 ) = 𝐶 → 𝐶 ∈ 𝐻 )
21 15 20 sylbir ⊢ ( 𝐴 = ( 𝐵 +ℎ 𝐶 ) → 𝐶 ∈ 𝐻 )
22 4 eleq2i ⊢ ( 𝐶 ∈ ( 𝐻 ∩ ( ⊥ ‘ 𝐺 ) ) ↔ 𝐶 ∈ 0ℋ )
23 elin ⊢ ( 𝐶 ∈ ( 𝐻 ∩ ( ⊥ ‘ 𝐺 ) ) ↔ ( 𝐶 ∈ 𝐻 ∧ 𝐶 ∈ ( ⊥ ‘ 𝐺 ) ) )
24 elch0 ⊢ ( 𝐶 ∈ 0ℋ ↔ 𝐶 = 0ℎ )
25 22 23 24 3bitr3i ⊢ ( ( 𝐶 ∈ 𝐻 ∧ 𝐶 ∈ ( ⊥ ‘ 𝐺 ) ) ↔ 𝐶 = 0ℎ )
26 21 7 25 sylanblc ⊢ ( 𝐴 = ( 𝐵 +ℎ 𝐶 ) → 𝐶 = 0ℎ )
27 26 oveq2d ⊢ ( 𝐴 = ( 𝐵 +ℎ 𝐶 ) → ( 𝐵 +ℎ 𝐶 ) = ( 𝐵 +ℎ 0ℎ ) )
28 ax-hvaddid ⊢ ( 𝐵 ∈ ℋ → ( 𝐵 +ℎ 0ℎ ) = 𝐵 )
29 9 28 ax-mp ⊢ ( 𝐵 +ℎ 0ℎ ) = 𝐵
30 27 29 eqtrdi ⊢ ( 𝐴 = ( 𝐵 +ℎ 𝐶 ) → ( 𝐵 +ℎ 𝐶 ) = 𝐵 )
31 30 6 eqeltrdi ⊢ ( 𝐴 = ( 𝐵 +ℎ 𝐶 ) → ( 𝐵 +ℎ 𝐶 ) ∈ 𝐺 )
32 eleq1 ⊢ ( 𝐴 = ( 𝐵 +ℎ 𝐶 ) → ( 𝐴 ∈ 𝐺 ↔ ( 𝐵 +ℎ 𝐶 ) ∈ 𝐺 ) )
33 31 32 mpbird ⊢ ( 𝐴 = ( 𝐵 +ℎ 𝐶 ) → 𝐴 ∈ 𝐺 )