Metamath Proof Explorer


Theorem oncardid

Description: Any ordinal number is equinumerous to its cardinal number. Unlike cardid , this theorem does not require the Axiom of Choice. (Contributed by NM, 26-Jul-2004)

Ref Expression
Assertion oncardid ( 𝐴 ∈ On → ( card ‘ 𝐴 ) ≈ 𝐴 )

Proof

Step Hyp Ref Expression
1 onenon ( 𝐴 ∈ On → 𝐴 ∈ dom card )
2 cardid2 ( 𝐴 ∈ dom card → ( card ‘ 𝐴 ) ≈ 𝐴 )
3 1 2 syl ( 𝐴 ∈ On → ( card ‘ 𝐴 ) ≈ 𝐴 )