Metamath Proof Explorer


Theorem op0le

Description: Orthoposet zero is less than or equal to any element. ( ch0le analog.) (Contributed by NM, 12-Oct-2011)

Ref Expression
Hypotheses op0le.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
op0le.l ⊢ ≤ = ( le ‘ 𝐾 )
op0le.z ⊢ 0 = ( 0. ‘ 𝐾 )
Assertion op0le ( ( 𝐾 ∈ OP ∧ 𝑋 ∈ 𝐵 ) → 0 ≤ 𝑋 )

Proof

Step Hyp Ref Expression
1 op0le.b ⊢ 𝐵 = ( Base ‘ 𝐾 )
2 op0le.l ⊢ ≤ = ( le ‘ 𝐾 )
3 op0le.z ⊢ 0 = ( 0. ‘ 𝐾 )
4 eqid ⊢ ( glb ‘ 𝐾 ) = ( glb ‘ 𝐾 )
5 simpl ⊢ ( ( 𝐾 ∈ OP ∧ 𝑋 ∈ 𝐵 ) → 𝐾 ∈ OP )
6 simpr ⊢ ( ( 𝐾 ∈ OP ∧ 𝑋 ∈ 𝐵 ) → 𝑋 ∈ 𝐵 )
7 eqid ⊢ ( lub ‘ 𝐾 ) = ( lub ‘ 𝐾 )
8 1 7 4 op01dm ⊢ ( 𝐾 ∈ OP → ( 𝐵 ∈ dom ( lub ‘ 𝐾 ) ∧ 𝐵 ∈ dom ( glb ‘ 𝐾 ) ) )
9 8 simprd ⊢ ( 𝐾 ∈ OP → 𝐵 ∈ dom ( glb ‘ 𝐾 ) )
10 9 adantr ⊢ ( ( 𝐾 ∈ OP ∧ 𝑋 ∈ 𝐵 ) → 𝐵 ∈ dom ( glb ‘ 𝐾 ) )
11 1 4 2 3 5 6 10 p0le ⊢ ( ( 𝐾 ∈ OP ∧ 𝑋 ∈ 𝐵 ) → 0 ≤ 𝑋 )