Metamath Proof Explorer
Description: Base set of an opposite ring. (Contributed by Mario Carneiro, 1-Dec-2014) (Proof shortened by AV, 6-Nov-2024)
|
|
Ref |
Expression |
|
Hypotheses |
opprbas.1 |
⊢ 𝑂 = ( oppr ‘ 𝑅 ) |
|
|
opprbas.2 |
⊢ 𝐵 = ( Base ‘ 𝑅 ) |
|
Assertion |
opprbas |
⊢ 𝐵 = ( Base ‘ 𝑂 ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
opprbas.1 |
⊢ 𝑂 = ( oppr ‘ 𝑅 ) |
| 2 |
|
opprbas.2 |
⊢ 𝐵 = ( Base ‘ 𝑅 ) |
| 3 |
|
baseid |
⊢ Base = Slot ( Base ‘ ndx ) |
| 4 |
|
basendxnmulrndx |
⊢ ( Base ‘ ndx ) ≠ ( .r ‘ ndx ) |
| 5 |
1 3 4
|
opprlem |
⊢ ( Base ‘ 𝑅 ) = ( Base ‘ 𝑂 ) |
| 6 |
2 5
|
eqtri |
⊢ 𝐵 = ( Base ‘ 𝑂 ) |