Metamath Proof Explorer


Theorem opprbas

Description: Base set of an opposite ring. (Contributed by Mario Carneiro, 1-Dec-2014)

Ref Expression
Hypotheses opprbas.1 𝑂 = ( oppr𝑅 )
opprbas.2 𝐵 = ( Base ‘ 𝑅 )
Assertion opprbas 𝐵 = ( Base ‘ 𝑂 )

Proof

Step Hyp Ref Expression
1 opprbas.1 𝑂 = ( oppr𝑅 )
2 opprbas.2 𝐵 = ( Base ‘ 𝑅 )
3 df-base Base = Slot 1
4 1nn 1 ∈ ℕ
5 1lt3 1 < 3
6 1 3 4 5 opprlem ( Base ‘ 𝑅 ) = ( Base ‘ 𝑂 )
7 2 6 eqtri 𝐵 = ( Base ‘ 𝑂 )