Description: Deduce implication from disjunction. (Contributed by NM, 18-May-1994)
Ref | Expression | ||
---|---|---|---|
Hypothesis | ord.1 | ⊢ ( 𝜑 → ( 𝜓 ∨ 𝜒 ) ) | |
Assertion | ord | ⊢ ( 𝜑 → ( ¬ 𝜓 → 𝜒 ) ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | ord.1 | ⊢ ( 𝜑 → ( 𝜓 ∨ 𝜒 ) ) | |
2 | df-or | ⊢ ( ( 𝜓 ∨ 𝜒 ) ↔ ( ¬ 𝜓 → 𝜒 ) ) | |
3 | 1 2 | sylib | ⊢ ( 𝜑 → ( ¬ 𝜓 → 𝜒 ) ) |