Metamath Proof Explorer


Theorem ordom

Description: The class of finite ordinals _om is ordinal. Theorem 7.32 of TakeutiZaring p. 43. (Contributed by NM, 18-Oct-1995) (Proof shortened by Andrew Salmon, 27-Aug-2011)

Ref Expression
Assertion ordom Ord ω

Proof

Step Hyp Ref Expression
1 trom Tr ω
2 omsson ω ⊆ On
3 ordon Ord On
4 trssord ( ( Tr ω ∧ ω ⊆ On ∧ Ord On ) → Ord ω )
5 1 2 3 4 mp3an Ord ω