Metamath Proof Explorer


Theorem oveq12i

Description: Equality inference for operation value. (Contributed by NM, 28-Feb-1995) (Proof shortened by Andrew Salmon, 22-Oct-2011)

Ref Expression
Hypotheses oveq1i.1 𝐴 = 𝐵
oveq12i.2 𝐶 = 𝐷
Assertion oveq12i ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 )

Proof

Step Hyp Ref Expression
1 oveq1i.1 𝐴 = 𝐵
2 oveq12i.2 𝐶 = 𝐷
3 oveq12 ( ( 𝐴 = 𝐵𝐶 = 𝐷 ) → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 ) )
4 1 2 3 mp2an ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐷 )