Metamath Proof Explorer


Theorem oveq1i

Description: Equality inference for operation value. (Contributed by NM, 28-Feb-1995)

Ref Expression
Hypothesis oveq1i.1 𝐴 = 𝐵
Assertion oveq1i ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐶 )

Proof

Step Hyp Ref Expression
1 oveq1i.1 𝐴 = 𝐵
2 oveq1 ( 𝐴 = 𝐵 → ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐶 ) )
3 1 2 ax-mp ( 𝐴 𝐹 𝐶 ) = ( 𝐵 𝐹 𝐶 )