Metamath Proof Explorer


Theorem oveq2d

Description: Equality deduction for operation value. (Contributed by NM, 13-Mar-1995)

Ref Expression
Hypothesis oveq1d.1 ( 𝜑𝐴 = 𝐵 )
Assertion oveq2d ( 𝜑 → ( 𝐶 𝐹 𝐴 ) = ( 𝐶 𝐹 𝐵 ) )

Proof

Step Hyp Ref Expression
1 oveq1d.1 ( 𝜑𝐴 = 𝐵 )
2 oveq2 ( 𝐴 = 𝐵 → ( 𝐶 𝐹 𝐴 ) = ( 𝐶 𝐹 𝐵 ) )
3 1 2 syl ( 𝜑 → ( 𝐶 𝐹 𝐴 ) = ( 𝐶 𝐹 𝐵 ) )