Metamath Proof Explorer


Theorem oveq2i

Description: Equality inference for operation value. (Contributed by NM, 28-Feb-1995)

Ref Expression
Hypothesis oveq1i.1 𝐴 = 𝐵
Assertion oveq2i ( 𝐶 𝐹 𝐴 ) = ( 𝐶 𝐹 𝐵 )

Proof

Step Hyp Ref Expression
1 oveq1i.1 𝐴 = 𝐵
2 oveq2 ( 𝐴 = 𝐵 → ( 𝐶 𝐹 𝐴 ) = ( 𝐶 𝐹 𝐵 ) )
3 1 2 ax-mp ( 𝐶 𝐹 𝐴 ) = ( 𝐶 𝐹 𝐵 )