Metamath Proof Explorer


Theorem oveqd

Description: Equality deduction for operation value. (Contributed by NM, 9-Sep-2006)

Ref Expression
Hypothesis oveq1d.1 ( 𝜑𝐴 = 𝐵 )
Assertion oveqd ( 𝜑 → ( 𝐶 𝐴 𝐷 ) = ( 𝐶 𝐵 𝐷 ) )

Proof

Step Hyp Ref Expression
1 oveq1d.1 ( 𝜑𝐴 = 𝐵 )
2 oveq ( 𝐴 = 𝐵 → ( 𝐶 𝐴 𝐷 ) = ( 𝐶 𝐵 𝐷 ) )
3 1 2 syl ( 𝜑 → ( 𝐶 𝐴 𝐷 ) = ( 𝐶 𝐵 𝐷 ) )