Metamath Proof Explorer


Theorem paddssat

Description: A projective subspace sum is a set of atoms. (Contributed by NM, 3-Jan-2012)

Ref Expression
Hypotheses padd0.a ⊢ 𝐴 = ( Atoms ‘ 𝐾 )
padd0.p ⊢ + = ( +𝑃 ‘ 𝐾 )
Assertion paddssat ( ( 𝐾 ∈ 𝐵 ∧ 𝑋 ⊆ 𝐴 ∧ 𝑌 ⊆ 𝐴 ) → ( 𝑋 + 𝑌 ) ⊆ 𝐴 )

Proof

Step Hyp Ref Expression
1 padd0.a ⊢ 𝐴 = ( Atoms ‘ 𝐾 )
2 padd0.p ⊢ + = ( +𝑃 ‘ 𝐾 )
3 eqid ⊢ ( le ‘ 𝐾 ) = ( le ‘ 𝐾 )
4 eqid ⊢ ( join ‘ 𝐾 ) = ( join ‘ 𝐾 )
5 3 4 1 2 paddval ⊢ ( ( 𝐾 ∈ 𝐵 ∧ 𝑋 ⊆ 𝐴 ∧ 𝑌 ⊆ 𝐴 ) → ( 𝑋 + 𝑌 ) = ( ( 𝑋 ∪ 𝑌 ) ∪ { 𝑝 ∈ 𝐴 ∣ ∃ 𝑞 ∈ 𝑋 ∃ 𝑟 ∈ 𝑌 𝑝 ( le ‘ 𝐾 ) ( 𝑞 ( join ‘ 𝐾 ) 𝑟 ) } ) )
6 unss ⊢ ( ( 𝑋 ⊆ 𝐴 ∧ 𝑌 ⊆ 𝐴 ) ↔ ( 𝑋 ∪ 𝑌 ) ⊆ 𝐴 )
7 6 biimpi ⊢ ( ( 𝑋 ⊆ 𝐴 ∧ 𝑌 ⊆ 𝐴 ) → ( 𝑋 ∪ 𝑌 ) ⊆ 𝐴 )
8 ssrab2 ⊢ { 𝑝 ∈ 𝐴 ∣ ∃ 𝑞 ∈ 𝑋 ∃ 𝑟 ∈ 𝑌 𝑝 ( le ‘ 𝐾 ) ( 𝑞 ( join ‘ 𝐾 ) 𝑟 ) } ⊆ 𝐴
9 7 8 jctir ⊢ ( ( 𝑋 ⊆ 𝐴 ∧ 𝑌 ⊆ 𝐴 ) → ( ( 𝑋 ∪ 𝑌 ) ⊆ 𝐴 ∧ { 𝑝 ∈ 𝐴 ∣ ∃ 𝑞 ∈ 𝑋 ∃ 𝑟 ∈ 𝑌 𝑝 ( le ‘ 𝐾 ) ( 𝑞 ( join ‘ 𝐾 ) 𝑟 ) } ⊆ 𝐴 ) )
10 unss ⊢ ( ( ( 𝑋 ∪ 𝑌 ) ⊆ 𝐴 ∧ { 𝑝 ∈ 𝐴 ∣ ∃ 𝑞 ∈ 𝑋 ∃ 𝑟 ∈ 𝑌 𝑝 ( le ‘ 𝐾 ) ( 𝑞 ( join ‘ 𝐾 ) 𝑟 ) } ⊆ 𝐴 ) ↔ ( ( 𝑋 ∪ 𝑌 ) ∪ { 𝑝 ∈ 𝐴 ∣ ∃ 𝑞 ∈ 𝑋 ∃ 𝑟 ∈ 𝑌 𝑝 ( le ‘ 𝐾 ) ( 𝑞 ( join ‘ 𝐾 ) 𝑟 ) } ) ⊆ 𝐴 )
11 9 10 sylib ⊢ ( ( 𝑋 ⊆ 𝐴 ∧ 𝑌 ⊆ 𝐴 ) → ( ( 𝑋 ∪ 𝑌 ) ∪ { 𝑝 ∈ 𝐴 ∣ ∃ 𝑞 ∈ 𝑋 ∃ 𝑟 ∈ 𝑌 𝑝 ( le ‘ 𝐾 ) ( 𝑞 ( join ‘ 𝐾 ) 𝑟 ) } ) ⊆ 𝐴 )
12 11 3adant1 ⊢ ( ( 𝐾 ∈ 𝐵 ∧ 𝑋 ⊆ 𝐴 ∧ 𝑌 ⊆ 𝐴 ) → ( ( 𝑋 ∪ 𝑌 ) ∪ { 𝑝 ∈ 𝐴 ∣ ∃ 𝑞 ∈ 𝑋 ∃ 𝑟 ∈ 𝑌 𝑝 ( le ‘ 𝐾 ) ( 𝑞 ( join ‘ 𝐾 ) 𝑟 ) } ) ⊆ 𝐴 )
13 5 12 eqsstrd ⊢ ( ( 𝐾 ∈ 𝐵 ∧ 𝑋 ⊆ 𝐴 ∧ 𝑌 ⊆ 𝐴 ) → ( 𝑋 + 𝑌 ) ⊆ 𝐴 )