Step |
Hyp |
Ref |
Expression |
1 |
|
eqid |
⊢ sup ( { 𝑥 ∈ ℕ0 ∣ ( 𝑃 ↑ 𝑥 ) ∥ 𝑁 } , ℝ , < ) = sup ( { 𝑥 ∈ ℕ0 ∣ ( 𝑃 ↑ 𝑥 ) ∥ 𝑁 } , ℝ , < ) |
2 |
1
|
pczpre |
⊢ ( ( 𝑃 ∈ ℙ ∧ ( 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) ) → ( 𝑃 pCnt 𝑁 ) = sup ( { 𝑥 ∈ ℕ0 ∣ ( 𝑃 ↑ 𝑥 ) ∥ 𝑁 } , ℝ , < ) ) |
3 |
|
prmuz2 |
⊢ ( 𝑃 ∈ ℙ → 𝑃 ∈ ( ℤ≥ ‘ 2 ) ) |
4 |
|
eqid |
⊢ { 𝑥 ∈ ℕ0 ∣ ( 𝑃 ↑ 𝑥 ) ∥ 𝑁 } = { 𝑥 ∈ ℕ0 ∣ ( 𝑃 ↑ 𝑥 ) ∥ 𝑁 } |
5 |
4 1
|
pcprecl |
⊢ ( ( 𝑃 ∈ ( ℤ≥ ‘ 2 ) ∧ ( 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) ) → ( sup ( { 𝑥 ∈ ℕ0 ∣ ( 𝑃 ↑ 𝑥 ) ∥ 𝑁 } , ℝ , < ) ∈ ℕ0 ∧ ( 𝑃 ↑ sup ( { 𝑥 ∈ ℕ0 ∣ ( 𝑃 ↑ 𝑥 ) ∥ 𝑁 } , ℝ , < ) ) ∥ 𝑁 ) ) |
6 |
3 5
|
sylan |
⊢ ( ( 𝑃 ∈ ℙ ∧ ( 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) ) → ( sup ( { 𝑥 ∈ ℕ0 ∣ ( 𝑃 ↑ 𝑥 ) ∥ 𝑁 } , ℝ , < ) ∈ ℕ0 ∧ ( 𝑃 ↑ sup ( { 𝑥 ∈ ℕ0 ∣ ( 𝑃 ↑ 𝑥 ) ∥ 𝑁 } , ℝ , < ) ) ∥ 𝑁 ) ) |
7 |
6
|
simpld |
⊢ ( ( 𝑃 ∈ ℙ ∧ ( 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) ) → sup ( { 𝑥 ∈ ℕ0 ∣ ( 𝑃 ↑ 𝑥 ) ∥ 𝑁 } , ℝ , < ) ∈ ℕ0 ) |
8 |
2 7
|
eqeltrd |
⊢ ( ( 𝑃 ∈ ℙ ∧ ( 𝑁 ∈ ℤ ∧ 𝑁 ≠ 0 ) ) → ( 𝑃 pCnt 𝑁 ) ∈ ℕ0 ) |