Metamath Proof Explorer


Theorem pj11i

Description: One-to-one correspondence of projection and subspace. (Contributed by NM, 26-Nov-2000) (New usage is discouraged.)

Ref Expression
Hypotheses pjsumt.1 ⊢ 𝐺 ∈ Cℋ
pjsumt.2 ⊢ 𝐻 ∈ Cℋ
Assertion pj11i ( ( projℎ ‘ 𝐺 ) = ( projℎ ‘ 𝐻 ) ↔ 𝐺 = 𝐻 )

Proof

Step Hyp Ref Expression
1 pjsumt.1 ⊢ 𝐺 ∈ Cℋ
2 pjsumt.2 ⊢ 𝐻 ∈ Cℋ
3 rneq ⊢ ( ( projℎ ‘ 𝐺 ) = ( projℎ ‘ 𝐻 ) → ran ( projℎ ‘ 𝐺 ) = ran ( projℎ ‘ 𝐻 ) )
4 1 pjrni ⊢ ran ( projℎ ‘ 𝐺 ) = 𝐺
5 2 pjrni ⊢ ran ( projℎ ‘ 𝐻 ) = 𝐻
6 3 4 5 3eqtr3g ⊢ ( ( projℎ ‘ 𝐺 ) = ( projℎ ‘ 𝐻 ) → 𝐺 = 𝐻 )
7 fveq2 ⊢ ( 𝐺 = 𝐻 → ( projℎ ‘ 𝐺 ) = ( projℎ ‘ 𝐻 ) )
8 6 7 impbii ⊢ ( ( projℎ ‘ 𝐺 ) = ( projℎ ‘ 𝐻 ) ↔ 𝐺 = 𝐻 )