Metamath Proof Explorer


Theorem pjoml5

Description: The orthomodular law. Remark in Kalmbach p. 22. (Contributed by NM, 12-Jun-2006) (New usage is discouraged.)

Ref Expression
Assertion pjoml5 ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( 𝐴 ∨ℋ ( ( ⊥ ‘ 𝐴 ) ∩ ( 𝐴 ∨ℋ 𝐵 ) ) ) = ( 𝐴 ∨ℋ 𝐵 ) )

Proof

Step Hyp Ref Expression
1 simpl ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → 𝐴 ∈ Cℋ )
2 chjcl ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( 𝐴 ∨ℋ 𝐵 ) ∈ Cℋ )
3 chub1 ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → 𝐴 ⊆ ( 𝐴 ∨ℋ 𝐵 ) )
4 pjoml2 ⊢ ( ( 𝐴 ∈ Cℋ ∧ ( 𝐴 ∨ℋ 𝐵 ) ∈ Cℋ ∧ 𝐴 ⊆ ( 𝐴 ∨ℋ 𝐵 ) ) → ( 𝐴 ∨ℋ ( ( ⊥ ‘ 𝐴 ) ∩ ( 𝐴 ∨ℋ 𝐵 ) ) ) = ( 𝐴 ∨ℋ 𝐵 ) )
5 1 2 3 4 syl3anc ⊢ ( ( 𝐴 ∈ Cℋ ∧ 𝐵 ∈ Cℋ ) → ( 𝐴 ∨ℋ ( ( ⊥ ‘ 𝐴 ) ∩ ( 𝐴 ∨ℋ 𝐵 ) ) ) = ( 𝐴 ∨ℋ 𝐵 ) )