Metamath Proof Explorer


Theorem ply1annidl

Description: The set Q of polynomials annihilating an element A forms an ideal. (Contributed by Thierry Arnoux, 9-Feb-2025)

Ref Expression
Hypotheses ply1annidl.o ⊢ 𝑂 = ( 𝑅 evalSub1 𝑆 )
ply1annidl.p ⊢ 𝑃 = ( Poly1 ‘ ( 𝑅 ↾s 𝑆 ) )
ply1annidl.b ⊢ 𝐵 = ( Base ‘ 𝑅 )
ply1annidl.r ⊢ ( 𝜑 → 𝑅 ∈ CRing )
ply1annidl.s ⊢ ( 𝜑 → 𝑆 ∈ ( SubRing ‘ 𝑅 ) )
ply1annidl.a ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
ply1annidl.0 ⊢ 0 = ( 0g ‘ 𝑅 )
ply1annidl.q ⊢ 𝑄 = { 𝑞 ∈ dom 𝑂 ∣ ( ( 𝑂 ‘ 𝑞 ) ‘ 𝐴 ) = 0 }
Assertion ply1annidl ( 𝜑 → 𝑄 ∈ ( LIdeal ‘ 𝑃 ) )

Proof

Step Hyp Ref Expression
1 ply1annidl.o ⊢ 𝑂 = ( 𝑅 evalSub1 𝑆 )
2 ply1annidl.p ⊢ 𝑃 = ( Poly1 ‘ ( 𝑅 ↾s 𝑆 ) )
3 ply1annidl.b ⊢ 𝐵 = ( Base ‘ 𝑅 )
4 ply1annidl.r ⊢ ( 𝜑 → 𝑅 ∈ CRing )
5 ply1annidl.s ⊢ ( 𝜑 → 𝑆 ∈ ( SubRing ‘ 𝑅 ) )
6 ply1annidl.a ⊢ ( 𝜑 → 𝐴 ∈ 𝐵 )
7 ply1annidl.0 ⊢ 0 = ( 0g ‘ 𝑅 )
8 ply1annidl.q ⊢ 𝑄 = { 𝑞 ∈ dom 𝑂 ∣ ( ( 𝑂 ‘ 𝑞 ) ‘ 𝐴 ) = 0 }
9 eqid ⊢ ( 𝑝 ∈ ( Base ‘ 𝑃 ) ↦ ( ( 𝑂 ‘ 𝑝 ) ‘ 𝐴 ) ) = ( 𝑝 ∈ ( Base ‘ 𝑃 ) ↦ ( ( 𝑂 ‘ 𝑝 ) ‘ 𝐴 ) )
10 1 2 3 4 5 6 7 8 9 ply1annidllem ⊢ ( 𝜑 → 𝑄 = ( ◡ ( 𝑝 ∈ ( Base ‘ 𝑃 ) ↦ ( ( 𝑂 ‘ 𝑝 ) ‘ 𝐴 ) ) “ { 0 } ) )
11 eqid ⊢ ( Base ‘ 𝑃 ) = ( Base ‘ 𝑃 )
12 1 2 3 11 4 5 6 9 evls1maprhm ⊢ ( 𝜑 → ( 𝑝 ∈ ( Base ‘ 𝑃 ) ↦ ( ( 𝑂 ‘ 𝑝 ) ‘ 𝐴 ) ) ∈ ( 𝑃 RingHom 𝑅 ) )
13 4 crngringd ⊢ ( 𝜑 → 𝑅 ∈ Ring )
14 eqid ⊢ ( LIdeal ‘ 𝑅 ) = ( LIdeal ‘ 𝑅 )
15 14 7 lidl0 ⊢ ( 𝑅 ∈ Ring → { 0 } ∈ ( LIdeal ‘ 𝑅 ) )
16 13 15 syl ⊢ ( 𝜑 → { 0 } ∈ ( LIdeal ‘ 𝑅 ) )
17 eqid ⊢ ( LIdeal ‘ 𝑃 ) = ( LIdeal ‘ 𝑃 )
18 17 rhmpreimaidl ⊢ ( ( ( 𝑝 ∈ ( Base ‘ 𝑃 ) ↦ ( ( 𝑂 ‘ 𝑝 ) ‘ 𝐴 ) ) ∈ ( 𝑃 RingHom 𝑅 ) ∧ { 0 } ∈ ( LIdeal ‘ 𝑅 ) ) → ( ◡ ( 𝑝 ∈ ( Base ‘ 𝑃 ) ↦ ( ( 𝑂 ‘ 𝑝 ) ‘ 𝐴 ) ) “ { 0 } ) ∈ ( LIdeal ‘ 𝑃 ) )
19 12 16 18 syl2anc ⊢ ( 𝜑 → ( ◡ ( 𝑝 ∈ ( Base ‘ 𝑃 ) ↦ ( ( 𝑂 ‘ 𝑝 ) ‘ 𝐴 ) ) “ { 0 } ) ∈ ( LIdeal ‘ 𝑃 ) )
20 10 19 eqeltrd ⊢ ( 𝜑 → 𝑄 ∈ ( LIdeal ‘ 𝑃 ) )