Metamath Proof Explorer


Theorem ply1dg1rtn0

Description: Polynomials of degree 1 over a field always have some roots. (Contributed by Thierry Arnoux, 8-Jun-2025)

Ref Expression
Hypotheses ply1dg1rt.p ⊢ 𝑃 = ( Poly1 ‘ 𝑅 )
ply1dg1rt.u ⊢ 𝑈 = ( Base ‘ 𝑃 )
ply1dg1rt.o ⊢ 𝑂 = ( eval1 ‘ 𝑅 )
ply1dg1rt.d ⊢ 𝐷 = ( deg1 ‘ 𝑅 )
ply1dg1rt.0 ⊢ 0 = ( 0g ‘ 𝑅 )
ply1dg1rtn0.r ⊢ ( 𝜑 → 𝑅 ∈ Field )
ply1dg1rtn0.g ⊢ ( 𝜑 → 𝐺 ∈ 𝑈 )
ply1dg1rtn0.1 ⊢ ( 𝜑 → ( 𝐷 ‘ 𝐺 ) = 1 )
Assertion ply1dg1rtn0 ( 𝜑 → ( ◡ ( 𝑂 ‘ 𝐺 ) “ { 0 } ) ≠ ∅ )

Proof

Step Hyp Ref Expression
1 ply1dg1rt.p ⊢ 𝑃 = ( Poly1 ‘ 𝑅 )
2 ply1dg1rt.u ⊢ 𝑈 = ( Base ‘ 𝑃 )
3 ply1dg1rt.o ⊢ 𝑂 = ( eval1 ‘ 𝑅 )
4 ply1dg1rt.d ⊢ 𝐷 = ( deg1 ‘ 𝑅 )
5 ply1dg1rt.0 ⊢ 0 = ( 0g ‘ 𝑅 )
6 ply1dg1rtn0.r ⊢ ( 𝜑 → 𝑅 ∈ Field )
7 ply1dg1rtn0.g ⊢ ( 𝜑 → 𝐺 ∈ 𝑈 )
8 ply1dg1rtn0.1 ⊢ ( 𝜑 → ( 𝐷 ‘ 𝐺 ) = 1 )
9 ovex ⊢ ( ( ( invg ‘ 𝑅 ) ‘ ( ( coe1 ‘ 𝐺 ) ‘ 0 ) ) ( /r ‘ 𝑅 ) ( ( coe1 ‘ 𝐺 ) ‘ 1 ) ) ∈ V
10 9 snid ⊢ ( ( ( invg ‘ 𝑅 ) ‘ ( ( coe1 ‘ 𝐺 ) ‘ 0 ) ) ( /r ‘ 𝑅 ) ( ( coe1 ‘ 𝐺 ) ‘ 1 ) ) ∈ { ( ( ( invg ‘ 𝑅 ) ‘ ( ( coe1 ‘ 𝐺 ) ‘ 0 ) ) ( /r ‘ 𝑅 ) ( ( coe1 ‘ 𝐺 ) ‘ 1 ) ) }
11 eqid ⊢ ( invg ‘ 𝑅 ) = ( invg ‘ 𝑅 )
12 eqid ⊢ ( /r ‘ 𝑅 ) = ( /r ‘ 𝑅 )
13 eqid ⊢ ( coe1 ‘ 𝐺 ) = ( coe1 ‘ 𝐺 )
14 eqid ⊢ ( ( coe1 ‘ 𝐺 ) ‘ 1 ) = ( ( coe1 ‘ 𝐺 ) ‘ 1 )
15 eqid ⊢ ( ( coe1 ‘ 𝐺 ) ‘ 0 ) = ( ( coe1 ‘ 𝐺 ) ‘ 0 )
16 eqid ⊢ ( ( ( invg ‘ 𝑅 ) ‘ ( ( coe1 ‘ 𝐺 ) ‘ 0 ) ) ( /r ‘ 𝑅 ) ( ( coe1 ‘ 𝐺 ) ‘ 1 ) ) = ( ( ( invg ‘ 𝑅 ) ‘ ( ( coe1 ‘ 𝐺 ) ‘ 0 ) ) ( /r ‘ 𝑅 ) ( ( coe1 ‘ 𝐺 ) ‘ 1 ) )
17 1 2 3 4 5 6 7 8 11 12 13 14 15 16 ply1dg1rt ⊢ ( 𝜑 → ( ◡ ( 𝑂 ‘ 𝐺 ) “ { 0 } ) = { ( ( ( invg ‘ 𝑅 ) ‘ ( ( coe1 ‘ 𝐺 ) ‘ 0 ) ) ( /r ‘ 𝑅 ) ( ( coe1 ‘ 𝐺 ) ‘ 1 ) ) } )
18 10 17 eleqtrrid ⊢ ( 𝜑 → ( ( ( invg ‘ 𝑅 ) ‘ ( ( coe1 ‘ 𝐺 ) ‘ 0 ) ) ( /r ‘ 𝑅 ) ( ( coe1 ‘ 𝐺 ) ‘ 1 ) ) ∈ ( ◡ ( 𝑂 ‘ 𝐺 ) “ { 0 } ) )
19 18 ne0d ⊢ ( 𝜑 → ( ◡ ( 𝑂 ‘ 𝐺 ) “ { 0 } ) ≠ ∅ )