Metamath Proof Explorer


Theorem ply1idom

Description: The ring of univariate polynomials over an integral domain is itself an integral domain. (Contributed by Stefan O'Rear, 29-Mar-2015)

Ref Expression
Hypothesis ply1domn.p ⊢ 𝑃 = ( Poly1 ‘ 𝑅 )
Assertion ply1idom ( 𝑅 ∈ IDomn → 𝑃 ∈ IDomn )

Proof

Step Hyp Ref Expression
1 ply1domn.p ⊢ 𝑃 = ( Poly1 ‘ 𝑅 )
2 1 ply1crng ⊢ ( 𝑅 ∈ CRing → 𝑃 ∈ CRing )
3 1 ply1domn ⊢ ( 𝑅 ∈ Domn → 𝑃 ∈ Domn )
4 2 3 anim12i ⊢ ( ( 𝑅 ∈ CRing ∧ 𝑅 ∈ Domn ) → ( 𝑃 ∈ CRing ∧ 𝑃 ∈ Domn ) )
5 isidom ⊢ ( 𝑅 ∈ IDomn ↔ ( 𝑅 ∈ CRing ∧ 𝑅 ∈ Domn ) )
6 isidom ⊢ ( 𝑃 ∈ IDomn ↔ ( 𝑃 ∈ CRing ∧ 𝑃 ∈ Domn ) )
7 4 5 6 3imtr4i ⊢ ( 𝑅 ∈ IDomn → 𝑃 ∈ IDomn )