Metamath Proof Explorer


Theorem pm13.195

Description: Theorem *13.195 in WhiteheadRussell p. 179. This theorem is very similar to sbc5 . (Contributed by Andrew Salmon, 3-Jun-2011) (Revised by NM, 4-Jan-2017)

Ref Expression
Assertion pm13.195 ( ∃ 𝑦 ( 𝑦 = 𝐴𝜑 ) ↔ [ 𝐴 / 𝑦 ] 𝜑 )

Proof

Step Hyp Ref Expression
1 sbc5 ( [ 𝐴 / 𝑦 ] 𝜑 ↔ ∃ 𝑦 ( 𝑦 = 𝐴𝜑 ) )
2 1 bicomi ( ∃ 𝑦 ( 𝑦 = 𝐴𝜑 ) ↔ [ 𝐴 / 𝑦 ] 𝜑 )