Metamath Proof Explorer


Theorem pm2.61d

Description: Deduction eliminating an antecedent. (Contributed by NM, 27-Apr-1994) (Proof shortened by Wolf Lammen, 12-Sep-2013)

Ref Expression
Hypotheses pm2.61d.1 ( 𝜑 → ( 𝜓𝜒 ) )
pm2.61d.2 ( 𝜑 → ( ¬ 𝜓𝜒 ) )
Assertion pm2.61d ( 𝜑𝜒 )

Proof

Step Hyp Ref Expression
1 pm2.61d.1 ( 𝜑 → ( 𝜓𝜒 ) )
2 pm2.61d.2 ( 𝜑 → ( ¬ 𝜓𝜒 ) )
3 2 con1d ( 𝜑 → ( ¬ 𝜒𝜓 ) )
4 3 1 syld ( 𝜑 → ( ¬ 𝜒𝜒 ) )
5 4 pm2.18d ( 𝜑𝜒 )