Metamath Proof Explorer
Description: Deduction eliminating an elementhood in an antecedent. (Contributed by AV, 5-Dec-2021)
|
|
Ref |
Expression |
|
Hypotheses |
pm2.61danel.1 |
⊢ ( ( 𝜑 ∧ 𝐴 ∈ 𝐵 ) → 𝜓 ) |
|
|
pm2.61danel.2 |
⊢ ( ( 𝜑 ∧ 𝐴 ∉ 𝐵 ) → 𝜓 ) |
|
Assertion |
pm2.61danel |
⊢ ( 𝜑 → 𝜓 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
pm2.61danel.1 |
⊢ ( ( 𝜑 ∧ 𝐴 ∈ 𝐵 ) → 𝜓 ) |
2 |
|
pm2.61danel.2 |
⊢ ( ( 𝜑 ∧ 𝐴 ∉ 𝐵 ) → 𝜓 ) |
3 |
|
df-nel |
⊢ ( 𝐴 ∉ 𝐵 ↔ ¬ 𝐴 ∈ 𝐵 ) |
4 |
3 2
|
sylan2br |
⊢ ( ( 𝜑 ∧ ¬ 𝐴 ∈ 𝐵 ) → 𝜓 ) |
5 |
1 4
|
pm2.61dan |
⊢ ( 𝜑 → 𝜓 ) |