Metamath Proof Explorer
Description: Inference eliminating two antecedents. (Contributed by NM, 4-Jan-1993)
(Proof shortened by Josh Purinton, 29-Dec-2000)
|
|
Ref |
Expression |
|
Hypotheses |
pm2.61ii.1 |
⊢ ( ¬ 𝜑 → ( ¬ 𝜓 → 𝜒 ) ) |
|
|
pm2.61ii.2 |
⊢ ( 𝜑 → 𝜒 ) |
|
|
pm2.61ii.3 |
⊢ ( 𝜓 → 𝜒 ) |
|
Assertion |
pm2.61ii |
⊢ 𝜒 |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
pm2.61ii.1 |
⊢ ( ¬ 𝜑 → ( ¬ 𝜓 → 𝜒 ) ) |
2 |
|
pm2.61ii.2 |
⊢ ( 𝜑 → 𝜒 ) |
3 |
|
pm2.61ii.3 |
⊢ ( 𝜓 → 𝜒 ) |
4 |
1 3
|
pm2.61d2 |
⊢ ( ¬ 𝜑 → 𝜒 ) |
5 |
2 4
|
pm2.61i |
⊢ 𝜒 |