Metamath Proof Explorer
Description: Deduction for proof by contradiction. (Contributed by NM, 26-Jun-1994)
(Proof shortened by Wolf Lammen, 26-May-2013)
|
|
Ref |
Expression |
|
Hypotheses |
pm2.65d.1 |
⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) ) |
|
|
pm2.65d.2 |
⊢ ( 𝜑 → ( 𝜓 → ¬ 𝜒 ) ) |
|
Assertion |
pm2.65d |
⊢ ( 𝜑 → ¬ 𝜓 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
pm2.65d.1 |
⊢ ( 𝜑 → ( 𝜓 → 𝜒 ) ) |
2 |
|
pm2.65d.2 |
⊢ ( 𝜑 → ( 𝜓 → ¬ 𝜒 ) ) |
3 |
2 1
|
nsyld |
⊢ ( 𝜑 → ( 𝜓 → ¬ 𝜓 ) ) |
4 |
3
|
pm2.01d |
⊢ ( 𝜑 → ¬ 𝜓 ) |