Metamath Proof Explorer


Theorem ppncand

Description: Cancellation law for mixed addition and subtraction. (Contributed by Mario Carneiro, 27-May-2016)

Ref Expression
Hypotheses negidd.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
pncand.2 ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
subaddd.3 ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
Assertion ppncand ( 𝜑 → ( ( 𝐴 + 𝐵 ) + ( 𝐶 − 𝐵 ) ) = ( 𝐴 + 𝐶 ) )

Proof

Step Hyp Ref Expression
1 negidd.1 ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2 pncand.2 ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
3 subaddd.3 ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
4 ppncan ⊢ ( ( 𝐴 ∈ ℂ ∧ 𝐵 ∈ ℂ ∧ 𝐶 ∈ ℂ ) → ( ( 𝐴 + 𝐵 ) + ( 𝐶 − 𝐵 ) ) = ( 𝐴 + 𝐶 ) )
5 1 2 3 4 syl3anc ⊢ ( 𝜑 → ( ( 𝐴 + 𝐵 ) + ( 𝐶 − 𝐵 ) ) = ( 𝐴 + 𝐶 ) )