Metamath Proof Explorer


Theorem prdsmulrcl

Description: A structure product of rings has closed binary operation. (Contributed by Mario Carneiro, 11-Mar-2015) (Proof shortened by AV, 30-Mar-2025)

Ref Expression
Hypotheses prdsmulrcl.y ⊢ 𝑌 = ( 𝑆 Xs 𝑅 )
prdsmulrcl.b ⊢ 𝐵 = ( Base ‘ 𝑌 )
prdsmulrcl.t ⊢ · = ( .r ‘ 𝑌 )
prdsmulrcl.s ⊢ ( 𝜑 → 𝑆 ∈ 𝑉 )
prdsmulrcl.i ⊢ ( 𝜑 → 𝐼 ∈ 𝑊 )
prdsmulrcl.r ⊢ ( 𝜑 → 𝑅 : 𝐼 ⟶ Ring )
prdsmulrcl.f ⊢ ( 𝜑 → 𝐹 ∈ 𝐵 )
prdsmulrcl.g ⊢ ( 𝜑 → 𝐺 ∈ 𝐵 )
Assertion prdsmulrcl ( 𝜑 → ( 𝐹 · 𝐺 ) ∈ 𝐵 )

Proof

Step Hyp Ref Expression
1 prdsmulrcl.y ⊢ 𝑌 = ( 𝑆 Xs 𝑅 )
2 prdsmulrcl.b ⊢ 𝐵 = ( Base ‘ 𝑌 )
3 prdsmulrcl.t ⊢ · = ( .r ‘ 𝑌 )
4 prdsmulrcl.s ⊢ ( 𝜑 → 𝑆 ∈ 𝑉 )
5 prdsmulrcl.i ⊢ ( 𝜑 → 𝐼 ∈ 𝑊 )
6 prdsmulrcl.r ⊢ ( 𝜑 → 𝑅 : 𝐼 ⟶ Ring )
7 prdsmulrcl.f ⊢ ( 𝜑 → 𝐹 ∈ 𝐵 )
8 prdsmulrcl.g ⊢ ( 𝜑 → 𝐺 ∈ 𝐵 )
9 ringssrng ⊢ Ring ⊆ Rng
10 fss ⊢ ( ( 𝑅 : 𝐼 ⟶ Ring ∧ Ring ⊆ Rng ) → 𝑅 : 𝐼 ⟶ Rng )
11 6 9 10 sylancl ⊢ ( 𝜑 → 𝑅 : 𝐼 ⟶ Rng )
12 1 2 3 4 5 11 7 8 prdsmulrngcl ⊢ ( 𝜑 → ( 𝐹 · 𝐺 ) ∈ 𝐵 )