Metamath Proof Explorer


Theorem prhash2ex

Description: There is (at least) one set with two different elements: the unordered pair containing 0 and 1 . In contrast to pr0hash2ex , numbers are used instead of sets because their representation is shorter (and more comprehensive). (Contributed by AV, 29-Jan-2020)

Ref Expression
Assertion prhash2ex ( ♯ ‘ { 0 , 1 } ) = 2

Proof

Step Hyp Ref Expression
1 0ne1 0 ≠ 1
2 c0ex 0 ∈ V
3 1ex 1 ∈ V
4 hashprg ( ( 0 ∈ V ∧ 1 ∈ V ) → ( 0 ≠ 1 ↔ ( ♯ ‘ { 0 , 1 } ) = 2 ) )
5 4 bicomd ( ( 0 ∈ V ∧ 1 ∈ V ) → ( ( ♯ ‘ { 0 , 1 } ) = 2 ↔ 0 ≠ 1 ) )
6 2 3 5 mp2an ( ( ♯ ‘ { 0 , 1 } ) = 2 ↔ 0 ≠ 1 )
7 1 6 mpbir ( ♯ ‘ { 0 , 1 } ) = 2