Metamath Proof Explorer


Theorem prmringnzring

Description: A prime ring is a nonzero ring. (Contributed by AV, 26-Jun-2026)

Ref Expression
Assertion prmringnzring ( 𝑅 ∈ PrmRing → 𝑅 ∈ NzRing )

Proof

Step Hyp Ref Expression
1 eqid ⊢ ( 0g ‘ 𝑅 ) = ( 0g ‘ 𝑅 )
2 eqid ⊢ ( PrmIdeal ‘ 𝑅 ) = ( PrmIdeal ‘ 𝑅 )
3 1 2 isprmrng ⊢ ( 𝑅 ∈ PrmRing ↔ ( 𝑅 ∈ Ring ∧ { ( 0g ‘ 𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) ) )
4 eqid ⊢ ( Base ‘ 𝑅 ) = ( Base ‘ 𝑅 )
5 4 0ringprmidl ⊢ ( ( 𝑅 ∈ Ring ∧ ( ♯ ‘ ( Base ‘ 𝑅 ) ) = 1 ) → ( PrmIdeal ‘ 𝑅 ) = ∅ )
6 eleq2 ⊢ ( ( PrmIdeal ‘ 𝑅 ) = ∅ → ( { ( 0g ‘ 𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) ↔ { ( 0g ‘ 𝑅 ) } ∈ ∅ ) )
7 noel ⊢ ¬ { ( 0g ‘ 𝑅 ) } ∈ ∅
8 7 pm2.21i ⊢ ( { ( 0g ‘ 𝑅 ) } ∈ ∅ → 𝑅 ∈ NzRing )
9 6 8 biimtrdi ⊢ ( ( PrmIdeal ‘ 𝑅 ) = ∅ → ( { ( 0g ‘ 𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) → 𝑅 ∈ NzRing ) )
10 5 9 syl ⊢ ( ( 𝑅 ∈ Ring ∧ ( ♯ ‘ ( Base ‘ 𝑅 ) ) = 1 ) → ( { ( 0g ‘ 𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) → 𝑅 ∈ NzRing ) )
11 10 ex ⊢ ( 𝑅 ∈ Ring → ( ( ♯ ‘ ( Base ‘ 𝑅 ) ) = 1 → ( { ( 0g ‘ 𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) → 𝑅 ∈ NzRing ) ) )
12 0ringnnzr ⊢ ( 𝑅 ∈ Ring → ( ( ♯ ‘ ( Base ‘ 𝑅 ) ) = 1 ↔ ¬ 𝑅 ∈ NzRing ) )
13 12 bicomd ⊢ ( 𝑅 ∈ Ring → ( ¬ 𝑅 ∈ NzRing ↔ ( ♯ ‘ ( Base ‘ 𝑅 ) ) = 1 ) )
14 13 con1bid ⊢ ( 𝑅 ∈ Ring → ( ¬ ( ♯ ‘ ( Base ‘ 𝑅 ) ) = 1 ↔ 𝑅 ∈ NzRing ) )
15 ax1w ⊢ ( 𝑅 ∈ Ring → ( 𝑅 ∈ NzRing → ( { ( 0g ‘ 𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) → 𝑅 ∈ NzRing ) ) )
16 14 15 sylbid ⊢ ( 𝑅 ∈ Ring → ( ¬ ( ♯ ‘ ( Base ‘ 𝑅 ) ) = 1 → ( { ( 0g ‘ 𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) → 𝑅 ∈ NzRing ) ) )
17 11 16 pm2.61d ⊢ ( 𝑅 ∈ Ring → ( { ( 0g ‘ 𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) → 𝑅 ∈ NzRing ) )
18 17 imp ⊢ ( ( 𝑅 ∈ Ring ∧ { ( 0g ‘ 𝑅 ) } ∈ ( PrmIdeal ‘ 𝑅 ) ) → 𝑅 ∈ NzRing )
19 3 18 sylbi ⊢ ( 𝑅 ∈ PrmRing → 𝑅 ∈ NzRing )