Metamath Proof Explorer


Theorem prodeq2

Description: Equality theorem for product. (Contributed by Scott Fenton, 4-Dec-2017)

Ref Expression
Assertion prodeq2 ( ∀ 𝑘𝐴 𝐵 = 𝐶 → ∏ 𝑘𝐴 𝐵 = ∏ 𝑘𝐴 𝐶 )

Proof

Step Hyp Ref Expression
1 fveq2 ( 𝐵 = 𝐶 → ( I ‘ 𝐵 ) = ( I ‘ 𝐶 ) )
2 1 ralimi ( ∀ 𝑘𝐴 𝐵 = 𝐶 → ∀ 𝑘𝐴 ( I ‘ 𝐵 ) = ( I ‘ 𝐶 ) )
3 prodeq2ii ( ∀ 𝑘𝐴 ( I ‘ 𝐵 ) = ( I ‘ 𝐶 ) → ∏ 𝑘𝐴 𝐵 = ∏ 𝑘𝐴 𝐶 )
4 2 3 syl ( ∀ 𝑘𝐴 𝐵 = 𝐶 → ∏ 𝑘𝐴 𝐵 = ∏ 𝑘𝐴 𝐶 )