Metamath Proof Explorer


Theorem pssnssi

Description: A proper subclass does not include the other class. (Contributed by Glauco Siliprandi, 26-Jun-2021)

Ref Expression
Hypothesis pssnssi.1 ⊢ 𝐴 ⊊ 𝐵
Assertion pssnssi ¬ 𝐵 ⊆ 𝐴

Proof

Step Hyp Ref Expression
1 pssnssi.1 ⊢ 𝐴 ⊊ 𝐵
2 dfpss3 ⊢ ( 𝐴 ⊊ 𝐵 ↔ ( 𝐴 ⊆ 𝐵 ∧ ¬ 𝐵 ⊆ 𝐴 ) )
3 1 2 mpbi ⊢ ( 𝐴 ⊆ 𝐵 ∧ ¬ 𝐵 ⊆ 𝐴 )
4 3 simpri ⊢ ¬ 𝐵 ⊆ 𝐴