Metamath Proof Explorer


Theorem pttop

Description: The product topology is a topology. (Contributed by Mario Carneiro, 3-Feb-2015)

Ref Expression
Assertion pttop ( ( 𝐴𝑉𝐹 : 𝐴 ⟶ Top ) → ( ∏t𝐹 ) ∈ Top )

Proof

Step Hyp Ref Expression
1 ffn ( 𝐹 : 𝐴 ⟶ Top → 𝐹 Fn 𝐴 )
2 eqid { 𝑥 ∣ ∃ 𝑔 ( ( 𝑔 Fn 𝐴 ∧ ∀ 𝑦𝐴 ( 𝑔𝑦 ) ∈ ( 𝐹𝑦 ) ∧ ∃ 𝑧 ∈ Fin ∀ 𝑦 ∈ ( 𝐴𝑧 ) ( 𝑔𝑦 ) = ( 𝐹𝑦 ) ) ∧ 𝑥 = X 𝑦𝐴 ( 𝑔𝑦 ) ) } = { 𝑥 ∣ ∃ 𝑔 ( ( 𝑔 Fn 𝐴 ∧ ∀ 𝑦𝐴 ( 𝑔𝑦 ) ∈ ( 𝐹𝑦 ) ∧ ∃ 𝑧 ∈ Fin ∀ 𝑦 ∈ ( 𝐴𝑧 ) ( 𝑔𝑦 ) = ( 𝐹𝑦 ) ) ∧ 𝑥 = X 𝑦𝐴 ( 𝑔𝑦 ) ) }
3 2 ptval ( ( 𝐴𝑉𝐹 Fn 𝐴 ) → ( ∏t𝐹 ) = ( topGen ‘ { 𝑥 ∣ ∃ 𝑔 ( ( 𝑔 Fn 𝐴 ∧ ∀ 𝑦𝐴 ( 𝑔𝑦 ) ∈ ( 𝐹𝑦 ) ∧ ∃ 𝑧 ∈ Fin ∀ 𝑦 ∈ ( 𝐴𝑧 ) ( 𝑔𝑦 ) = ( 𝐹𝑦 ) ) ∧ 𝑥 = X 𝑦𝐴 ( 𝑔𝑦 ) ) } ) )
4 1 3 sylan2 ( ( 𝐴𝑉𝐹 : 𝐴 ⟶ Top ) → ( ∏t𝐹 ) = ( topGen ‘ { 𝑥 ∣ ∃ 𝑔 ( ( 𝑔 Fn 𝐴 ∧ ∀ 𝑦𝐴 ( 𝑔𝑦 ) ∈ ( 𝐹𝑦 ) ∧ ∃ 𝑧 ∈ Fin ∀ 𝑦 ∈ ( 𝐴𝑧 ) ( 𝑔𝑦 ) = ( 𝐹𝑦 ) ) ∧ 𝑥 = X 𝑦𝐴 ( 𝑔𝑦 ) ) } ) )
5 2 ptbas ( ( 𝐴𝑉𝐹 : 𝐴 ⟶ Top ) → { 𝑥 ∣ ∃ 𝑔 ( ( 𝑔 Fn 𝐴 ∧ ∀ 𝑦𝐴 ( 𝑔𝑦 ) ∈ ( 𝐹𝑦 ) ∧ ∃ 𝑧 ∈ Fin ∀ 𝑦 ∈ ( 𝐴𝑧 ) ( 𝑔𝑦 ) = ( 𝐹𝑦 ) ) ∧ 𝑥 = X 𝑦𝐴 ( 𝑔𝑦 ) ) } ∈ TopBases )
6 tgcl ( { 𝑥 ∣ ∃ 𝑔 ( ( 𝑔 Fn 𝐴 ∧ ∀ 𝑦𝐴 ( 𝑔𝑦 ) ∈ ( 𝐹𝑦 ) ∧ ∃ 𝑧 ∈ Fin ∀ 𝑦 ∈ ( 𝐴𝑧 ) ( 𝑔𝑦 ) = ( 𝐹𝑦 ) ) ∧ 𝑥 = X 𝑦𝐴 ( 𝑔𝑦 ) ) } ∈ TopBases → ( topGen ‘ { 𝑥 ∣ ∃ 𝑔 ( ( 𝑔 Fn 𝐴 ∧ ∀ 𝑦𝐴 ( 𝑔𝑦 ) ∈ ( 𝐹𝑦 ) ∧ ∃ 𝑧 ∈ Fin ∀ 𝑦 ∈ ( 𝐴𝑧 ) ( 𝑔𝑦 ) = ( 𝐹𝑦 ) ) ∧ 𝑥 = X 𝑦𝐴 ( 𝑔𝑦 ) ) } ) ∈ Top )
7 5 6 syl ( ( 𝐴𝑉𝐹 : 𝐴 ⟶ Top ) → ( topGen ‘ { 𝑥 ∣ ∃ 𝑔 ( ( 𝑔 Fn 𝐴 ∧ ∀ 𝑦𝐴 ( 𝑔𝑦 ) ∈ ( 𝐹𝑦 ) ∧ ∃ 𝑧 ∈ Fin ∀ 𝑦 ∈ ( 𝐴𝑧 ) ( 𝑔𝑦 ) = ( 𝐹𝑦 ) ) ∧ 𝑥 = X 𝑦𝐴 ( 𝑔𝑦 ) ) } ) ∈ Top )
8 4 7 eqeltrd ( ( 𝐴𝑉𝐹 : 𝐴 ⟶ Top ) → ( ∏t𝐹 ) ∈ Top )