Metamath Proof Explorer
Description: Equality theorem for power class. (Contributed by NM, 21-Jun-1993)
(Proof shortened by BJ, 13-Apr-2024)
|
|
Ref |
Expression |
|
Assertion |
pweq |
⊢ ( 𝐴 = 𝐵 → 𝒫 𝐴 = 𝒫 𝐵 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
eqimss |
⊢ ( 𝐴 = 𝐵 → 𝐴 ⊆ 𝐵 ) |
2 |
1
|
sspwd |
⊢ ( 𝐴 = 𝐵 → 𝒫 𝐴 ⊆ 𝒫 𝐵 ) |
3 |
|
eqimss2 |
⊢ ( 𝐴 = 𝐵 → 𝐵 ⊆ 𝐴 ) |
4 |
3
|
sspwd |
⊢ ( 𝐴 = 𝐵 → 𝒫 𝐵 ⊆ 𝒫 𝐴 ) |
5 |
2 4
|
eqssd |
⊢ ( 𝐴 = 𝐵 → 𝒫 𝐴 = 𝒫 𝐵 ) |