Metamath Proof Explorer


Theorem quad

Description: The quadratic equation. (Contributed by Mario Carneiro, 23-Apr-2015)

Ref Expression
Hypotheses quad.a ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
quad.z ⊢ ( 𝜑 → 𝐴 ≠ 0 )
quad.b ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
quad.c ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
quad.x ⊢ ( 𝜑 → 𝑋 ∈ ℂ )
quad.d ⊢ ( 𝜑 → 𝐷 = ( ( 𝐵 ↑ 2 ) − ( 4 · ( 𝐴 · 𝐶 ) ) ) )
Assertion quad ( 𝜑 → ( ( ( 𝐴 · ( 𝑋 ↑ 2 ) ) + ( ( 𝐵 · 𝑋 ) + 𝐶 ) ) = 0 ↔ ( 𝑋 = ( ( - 𝐵 + ( √ ‘ 𝐷 ) ) / ( 2 · 𝐴 ) ) ∨ 𝑋 = ( ( - 𝐵 − ( √ ‘ 𝐷 ) ) / ( 2 · 𝐴 ) ) ) ) )

Proof

Step Hyp Ref Expression
1 quad.a ⊢ ( 𝜑 → 𝐴 ∈ ℂ )
2 quad.z ⊢ ( 𝜑 → 𝐴 ≠ 0 )
3 quad.b ⊢ ( 𝜑 → 𝐵 ∈ ℂ )
4 quad.c ⊢ ( 𝜑 → 𝐶 ∈ ℂ )
5 quad.x ⊢ ( 𝜑 → 𝑋 ∈ ℂ )
6 quad.d ⊢ ( 𝜑 → 𝐷 = ( ( 𝐵 ↑ 2 ) − ( 4 · ( 𝐴 · 𝐶 ) ) ) )
7 3 sqcld ⊢ ( 𝜑 → ( 𝐵 ↑ 2 ) ∈ ℂ )
8 4cn ⊢ 4 ∈ ℂ
9 1 4 mulcld ⊢ ( 𝜑 → ( 𝐴 · 𝐶 ) ∈ ℂ )
10 mulcl ⊢ ( ( 4 ∈ ℂ ∧ ( 𝐴 · 𝐶 ) ∈ ℂ ) → ( 4 · ( 𝐴 · 𝐶 ) ) ∈ ℂ )
11 8 9 10 sylancr ⊢ ( 𝜑 → ( 4 · ( 𝐴 · 𝐶 ) ) ∈ ℂ )
12 7 11 subcld ⊢ ( 𝜑 → ( ( 𝐵 ↑ 2 ) − ( 4 · ( 𝐴 · 𝐶 ) ) ) ∈ ℂ )
13 6 12 eqeltrd ⊢ ( 𝜑 → 𝐷 ∈ ℂ )
14 13 sqrtcld ⊢ ( 𝜑 → ( √ ‘ 𝐷 ) ∈ ℂ )
15 13 sqsqrtd ⊢ ( 𝜑 → ( ( √ ‘ 𝐷 ) ↑ 2 ) = 𝐷 )
16 15 6 eqtrd ⊢ ( 𝜑 → ( ( √ ‘ 𝐷 ) ↑ 2 ) = ( ( 𝐵 ↑ 2 ) − ( 4 · ( 𝐴 · 𝐶 ) ) ) )
17 1 2 3 4 5 14 16 quad2 ⊢ ( 𝜑 → ( ( ( 𝐴 · ( 𝑋 ↑ 2 ) ) + ( ( 𝐵 · 𝑋 ) + 𝐶 ) ) = 0 ↔ ( 𝑋 = ( ( - 𝐵 + ( √ ‘ 𝐷 ) ) / ( 2 · 𝐴 ) ) ∨ 𝑋 = ( ( - 𝐵 − ( √ ‘ 𝐷 ) ) / ( 2 · 𝐴 ) ) ) ) )