Metamath Proof Explorer
Description: Version of rabbidv with disjoint variable condition replaced by
nonfreeness hypothesis. (Contributed by BJ, 27-Apr-2019)
|
|
Ref |
Expression |
|
Hypotheses |
rabbid.n |
⊢ Ⅎ 𝑥 𝜑 |
|
|
rabbid.1 |
⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |
|
Assertion |
rabbid |
⊢ ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } = { 𝑥 ∈ 𝐴 ∣ 𝜒 } ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
rabbid.n |
⊢ Ⅎ 𝑥 𝜑 |
2 |
|
rabbid.1 |
⊢ ( 𝜑 → ( 𝜓 ↔ 𝜒 ) ) |
3 |
2
|
adantr |
⊢ ( ( 𝜑 ∧ 𝑥 ∈ 𝐴 ) → ( 𝜓 ↔ 𝜒 ) ) |
4 |
1 3
|
rabbida |
⊢ ( 𝜑 → { 𝑥 ∈ 𝐴 ∣ 𝜓 } = { 𝑥 ∈ 𝐴 ∣ 𝜒 } ) |