Metamath Proof Explorer
		
		
		
		Description:  Version of rabbidv with disjoint variable condition replaced by
       nonfreeness hypothesis.  (Contributed by BJ, 27-Apr-2019)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | rabbid.n | ⊢ Ⅎ 𝑥 𝜑 | 
					
						|  |  | rabbid.1 | ⊢ ( 𝜑  →  ( 𝜓  ↔  𝜒 ) ) | 
				
					|  | Assertion | rabbid | ⊢  ( 𝜑  →  { 𝑥  ∈  𝐴  ∣  𝜓 }  =  { 𝑥  ∈  𝐴  ∣  𝜒 } ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | rabbid.n | ⊢ Ⅎ 𝑥 𝜑 | 
						
							| 2 |  | rabbid.1 | ⊢ ( 𝜑  →  ( 𝜓  ↔  𝜒 ) ) | 
						
							| 3 | 2 | adantr | ⊢ ( ( 𝜑  ∧  𝑥  ∈  𝐴 )  →  ( 𝜓  ↔  𝜒 ) ) | 
						
							| 4 | 1 3 | rabbida | ⊢ ( 𝜑  →  { 𝑥  ∈  𝐴  ∣  𝜓 }  =  { 𝑥  ∈  𝐴  ∣  𝜒 } ) |