Metamath Proof Explorer


Theorem recnd

Description: Deduction from real number to complex number. (Contributed by NM, 26-Oct-1999)

Ref Expression
Hypothesis recnd.1 ( 𝜑𝐴 ∈ ℝ )
Assertion recnd ( 𝜑𝐴 ∈ ℂ )

Proof

Step Hyp Ref Expression
1 recnd.1 ( 𝜑𝐴 ∈ ℝ )
2 recn ( 𝐴 ∈ ℝ → 𝐴 ∈ ℂ )
3 1 2 syl ( 𝜑𝐴 ∈ ℂ )