Metamath Proof Explorer


Theorem relcnvtrg

Description: Subclass law for converse of a composition. A particular case is ( ( R o. R ) C_ R <-> (`' R o. ``' R ) C_ ``' R ) ` , which says that a relation is transitive iff its converse is transitive. (Contributed by FL, 19-Sep-2011) Generalize to a statement about three classes rather than one. (Revised by Peter Mazsa, 17-Oct-2023) Remove antecedent. (Revised by Eric Schmidt, 8-Aug-2026)

Ref Expression
Assertion relcnvtrg ( ( 𝑅𝑆 ) ⊆ 𝑇 ↔ ( 𝑆 𝑅 ) ⊆ 𝑇 )

Proof

Step Hyp Ref Expression
1 cnvco ( 𝑅𝑆 ) = ( 𝑆 𝑅 )
2 cnvss ( ( 𝑅𝑆 ) ⊆ 𝑇 ( 𝑅𝑆 ) ⊆ 𝑇 )
3 1 2 eqsstrrid ( ( 𝑅𝑆 ) ⊆ 𝑇 → ( 𝑆 𝑅 ) ⊆ 𝑇 )
4 cnvco ( 𝑆 𝑅 ) = ( 𝑅 𝑆 )
5 cocnvcnv1 ( 𝑅 𝑆 ) = ( 𝑅 𝑆 )
6 cocnvcnv2 ( 𝑅 𝑆 ) = ( 𝑅𝑆 )
7 4 5 6 3eqtri ( 𝑆 𝑅 ) = ( 𝑅𝑆 )
8 cnvss ( ( 𝑆 𝑅 ) ⊆ 𝑇 ( 𝑆 𝑅 ) ⊆ 𝑇 )
9 7 8 eqsstrrid ( ( 𝑆 𝑅 ) ⊆ 𝑇 → ( 𝑅𝑆 ) ⊆ 𝑇 )
10 cnvcnvss 𝑇𝑇
11 9 10 sstrdi ( ( 𝑆 𝑅 ) ⊆ 𝑇 → ( 𝑅𝑆 ) ⊆ 𝑇 )
12 3 11 impbii ( ( 𝑅𝑆 ) ⊆ 𝑇 ↔ ( 𝑆 𝑅 ) ⊆ 𝑇 )