Metamath Proof Explorer


Theorem reldif

Description: A difference cutting down a relation is a relation. (Contributed by NM, 31-Mar-1998)

Ref Expression
Assertion reldif ( Rel 𝐴 → Rel ( 𝐴𝐵 ) )

Proof

Step Hyp Ref Expression
1 difss ( 𝐴𝐵 ) ⊆ 𝐴
2 relss ( ( 𝐴𝐵 ) ⊆ 𝐴 → ( Rel 𝐴 → Rel ( 𝐴𝐵 ) ) )
3 1 2 ax-mp ( Rel 𝐴 → Rel ( 𝐴𝐵 ) )