Metamath Proof Explorer


Theorem relssdmrn

Description: A relation is included in the Cartesian product of its domain and range. Exercise 4.12(t) of Mendelson p. 235. (Contributed by NM, 3-Aug-1994) (Proof shortened by SN, 23-Dec-2024)

Ref Expression
Assertion relssdmrn ( Rel 𝐴𝐴 ⊆ ( dom 𝐴 × ran 𝐴 ) )

Proof

Step Hyp Ref Expression
1 id ( Rel 𝐴 → Rel 𝐴 )
2 vex 𝑥 ∈ V
3 vex 𝑦 ∈ V
4 2 3 opeldm ( ⟨ 𝑥 , 𝑦 ⟩ ∈ 𝐴𝑥 ∈ dom 𝐴 )
5 2 3 opelrn ( ⟨ 𝑥 , 𝑦 ⟩ ∈ 𝐴𝑦 ∈ ran 𝐴 )
6 4 5 opelxpd ( ⟨ 𝑥 , 𝑦 ⟩ ∈ 𝐴 → ⟨ 𝑥 , 𝑦 ⟩ ∈ ( dom 𝐴 × ran 𝐴 ) )
7 6 a1i ( Rel 𝐴 → ( ⟨ 𝑥 , 𝑦 ⟩ ∈ 𝐴 → ⟨ 𝑥 , 𝑦 ⟩ ∈ ( dom 𝐴 × ran 𝐴 ) ) )
8 1 7 relssdv ( Rel 𝐴𝐴 ⊆ ( dom 𝐴 × ran 𝐴 ) )