Metamath Proof Explorer


Theorem renegi

Description: Real part of negative. (Contributed by NM, 2-Aug-1999)

Ref Expression
Hypothesis recl.1 𝐴 ∈ ℂ
Assertion renegi ( ℜ ‘ - 𝐴 ) = - ( ℜ ‘ 𝐴 )

Proof

Step Hyp Ref Expression
1 recl.1 𝐴 ∈ ℂ
2 reneg ( 𝐴 ∈ ℂ → ( ℜ ‘ - 𝐴 ) = - ( ℜ ‘ 𝐴 ) )
3 1 2 ax-mp ( ℜ ‘ - 𝐴 ) = - ( ℜ ‘ 𝐴 )