Metamath Proof Explorer


Theorem reseq1i

Description: Equality inference for restrictions. (Contributed by NM, 21-Oct-2014)

Ref Expression
Hypothesis reseqi.1 𝐴 = 𝐵
Assertion reseq1i ( 𝐴𝐶 ) = ( 𝐵𝐶 )

Proof

Step Hyp Ref Expression
1 reseqi.1 𝐴 = 𝐵
2 reseq1 ( 𝐴 = 𝐵 → ( 𝐴𝐶 ) = ( 𝐵𝐶 ) )
3 1 2 ax-mp ( 𝐴𝐶 ) = ( 𝐵𝐶 )