Metamath Proof Explorer


Theorem resfnfinfin

Description: The restriction of a function to a finite set is finite. (Contributed by Alexander van der Vekens, 3-Feb-2018)

Ref Expression
Assertion resfnfinfin ( ( 𝐹 Fn 𝐴𝐵 ∈ Fin ) → ( 𝐹𝐵 ) ∈ Fin )

Proof

Step Hyp Ref Expression
1 resindm ( 𝐹 ↾ ( 𝐵 ∩ dom 𝐹 ) ) = ( 𝐹𝐵 )
2 fnfun ( 𝐹 Fn 𝐴 → Fun 𝐹 )
3 2 funfnd ( 𝐹 Fn 𝐴𝐹 Fn dom 𝐹 )
4 fnresin2 ( 𝐹 Fn dom 𝐹 → ( 𝐹 ↾ ( 𝐵 ∩ dom 𝐹 ) ) Fn ( 𝐵 ∩ dom 𝐹 ) )
5 infi ( 𝐵 ∈ Fin → ( 𝐵 ∩ dom 𝐹 ) ∈ Fin )
6 fnfi ( ( ( 𝐹 ↾ ( 𝐵 ∩ dom 𝐹 ) ) Fn ( 𝐵 ∩ dom 𝐹 ) ∧ ( 𝐵 ∩ dom 𝐹 ) ∈ Fin ) → ( 𝐹 ↾ ( 𝐵 ∩ dom 𝐹 ) ) ∈ Fin )
7 5 6 sylan2 ( ( ( 𝐹 ↾ ( 𝐵 ∩ dom 𝐹 ) ) Fn ( 𝐵 ∩ dom 𝐹 ) ∧ 𝐵 ∈ Fin ) → ( 𝐹 ↾ ( 𝐵 ∩ dom 𝐹 ) ) ∈ Fin )
8 7 ex ( ( 𝐹 ↾ ( 𝐵 ∩ dom 𝐹 ) ) Fn ( 𝐵 ∩ dom 𝐹 ) → ( 𝐵 ∈ Fin → ( 𝐹 ↾ ( 𝐵 ∩ dom 𝐹 ) ) ∈ Fin ) )
9 3 4 8 3syl ( 𝐹 Fn 𝐴 → ( 𝐵 ∈ Fin → ( 𝐹 ↾ ( 𝐵 ∩ dom 𝐹 ) ) ∈ Fin ) )
10 9 imp ( ( 𝐹 Fn 𝐴𝐵 ∈ Fin ) → ( 𝐹 ↾ ( 𝐵 ∩ dom 𝐹 ) ) ∈ Fin )
11 1 10 eqeltrrid ( ( 𝐹 Fn 𝐴𝐵 ∈ Fin ) → ( 𝐹𝐵 ) ∈ Fin )