Metamath Proof Explorer


Theorem reuxfr1ds

Description: Transfer existential uniqueness from a variable x to another variable y contained in expression A . Use reuhypd to eliminate the second hypothesis. (Contributed by NM, 16-Jan-2012)

Ref Expression
Hypotheses reuxfr1ds.1 ( ( 𝜑𝑦𝐶 ) → 𝐴𝐵 )
reuxfr1ds.2 ( ( 𝜑𝑥𝐵 ) → ∃! 𝑦𝐶 𝑥 = 𝐴 )
reuxfr1ds.3 ( 𝑥 = 𝐴 → ( 𝜓𝜒 ) )
Assertion reuxfr1ds ( 𝜑 → ( ∃! 𝑥𝐵 𝜓 ↔ ∃! 𝑦𝐶 𝜒 ) )

Proof

Step Hyp Ref Expression
1 reuxfr1ds.1 ( ( 𝜑𝑦𝐶 ) → 𝐴𝐵 )
2 reuxfr1ds.2 ( ( 𝜑𝑥𝐵 ) → ∃! 𝑦𝐶 𝑥 = 𝐴 )
3 reuxfr1ds.3 ( 𝑥 = 𝐴 → ( 𝜓𝜒 ) )
4 3 adantl ( ( 𝜑𝑥 = 𝐴 ) → ( 𝜓𝜒 ) )
5 1 2 4 reuxfr1d ( 𝜑 → ( ∃! 𝑥𝐵 𝜓 ↔ ∃! 𝑦𝐶 𝜒 ) )